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Results after Problem 7

The list of the contest leaders after the seventh problem:

Points   Name Country School Physics teacher
18,869   Sabó Attila Hungary Leőwey Klára High School, Pécs Simon Péter, Dr Kotek László
16,602   Nikita Sopenko Russia Lyceum No.14, Tambov Valeriy Vladimirovich Biryukov
11,576   Jakub Šafin Slovak Pavol Horov Secondary, Michalovce Jozef Smrek
11,188   Ilie Popanu Moldova Lyceuum "Orizont", Chisinau Igor Evtodiev
10,818   Lars Dehlwes Germany Ohm-Gymnasium Erlangen Martin Perleth
8,5043   Ion Toloaca Moldova liceul "Mircea Eliade" Igor Iurevici Nemtov; Andrei Simboteanu
7,9569   Alexandra Vasileva Russia Lyceum "Second School", Moscow A.R. Zilberman, G.F. Lvovskaya, G.Z. Arabuly 
7,8933   Ivan Tadeu Ferreira Antunes Filho Brazil Colégio Objetivo, Lins, São Paulo  
7,7917   Nadezhda Vartanian Russia Smolensk Pedagogical Lyceum Mishchenko Andrei Anatolievich
7,4407   Dinis Cheian Moldova Lyceuum "Orizont", Chisinau Igor Evtodiev
7,0844   Cristian Zanoci Moldova Lyceuum "Orizont", Chisinau Igor Evtodiev
6,8529   Jakub Supeł  Poland 14th School of Stanisław Staszic, Warsaw Włodzimierz Zielicz
6,5644   Kohei Kawabata Japan Nada High School  
5,8911   Papimeri Dumitru Moldova Lyceuum "Orizont", Chisinau Igor Evtodiev
5,6695   Brahim Saadi Algeria Preparatory School for Science & Technology of Annaba Derradji Nasreddine
4,2965   Petar Tadic Montenegro Gimnazija ,,Stojan Cerovic" Niksic Ana Vujacic
3,7517   Luís Gustavo Lapinha Dalla Stella Brazil Colégio Integrado Objetivo, Barueri, Brazil Ronaldo Fogo
3,4205   Bharadwaj Rallabandi India Narayana Jr. College, Basheer Bagh, India Vyom Sekhar Singh
3,1554   Selver Pepić Bosnia-Herzegovina Fourth Gymnasium Ilidža, Sarajevo Rajfa Musemić
3,0862   Ng Fei Chong Malaysia SMJK Chung Ling, Penang  
2,7716    Adrian Nugraha Utama Indonesia SMA Sutomo 1 Medan Manaek Nababan
2,5937   Mikhail Shirkin Russia Gymnasium of  Ramenskoye  Petrova Elena Georgyevna
2,374   Lorenzo Comoglio  Italy Liceo Scientifico del Cossatese e Valle Strona Chiara Bandini
2,2747   Kai-Chi Huang Taiwan Taipei Municipal Chien-Kuo High School Shun-Ju Liu
2,1   Krzysztof Markiewicz Poland XIV Highschool in Warsaw Robert Stasiak
2   Teoh Yee Seng Malaysia SMJK HENG EE,Penang; SMJK CHUNG LING,Penang  
2   Jaan Toots Estonia Tallinn Secondary Science School Toomas Reimann
1,7444   Andrew Zhao United States Webster Thomas High School Dykstra, William 
1,4641   Hideki Yukawa Japan Nada high school  
1,4641   Bruno Bento Barros de Araújo Brazil Ari de Sá Cavalcante Edney Melo
1,21   Midhul Varma India Vidyadham Junior, Hyderabad  Manikanta Kumar
1   Task Ohmori Japan Nada High School T.Hamaguchi
1   Sharad Mirani  India Prakash Higher Secondary School Ruchi Sadana, Sunil Sharma
1   Lev Ginzburg Russia Advanced Educational Scientific Center, MSU, Moscow I.V. Lukjanov, S.N. Oks
1   José Luciano de Morais Neto Brazil Colégio Ari de Sá Cavalcante Leonardo Bruno
0,9801   Mekan Toyjanow Turkmenistan Turgut Ozal Turkmen Turkish High School Halit Coshkun
0,9   Jôhanes Sebástian Paiva Melo Brazil Colégio Ari de Sá Cavalcante Eduardo Kilder; Italo Reann
0,81   Meylis Malikov Turkmenistan Turgut Ozal Turkmen Turkish High School Halit Coshkun
0,81   Liara Guinsberg Brazil Colégio Integrado Objetivo, São Paulo, Brazil Ronaldo Fogo
0,792   Ulysse Lojkine  France Lycée Henri IV, Paris M. Lacas
0,72   Rajat Sharma India Pragati Vidya Peeth,Gwalior Mr. Rakesh Ranjan

 

Points for Problem No 7:

3,2913   Sabó Attila
2,9921   Nadezhda Vartanian
2,72   Jakub Šafin
2,4728   Nikita Sopenko
1,7716    Adrian Nugraha Utama
1,7538   Alexandra Vasileva
1,6889   Ilie Popanu
1,6105   Selver Pepić
1,5354   Ion Toloaca
1,089   Petar Tadic
1   Lars Dehlwes
1   Ivan Tadeu Ferreira Antunes Filho
1   Dinis Cheian
1   Cristian Zanoci
1   Kohei Kawabata
1   Teoh Yee Seng
0,9344   Andrew Zhao
0,9   Ng Fei Chong
0,6561   Jakub Supeł 

 

Correct solutions (ordered according to the arrival time; best solutions in bold):

1. Szabó Attila (Hungary)

2. Nadezhda Vartanian (Russia)

3. Jakub Šafin (Slovak)

4. Nikita Sopenko (Russia)

5. Alexandra Vasileva (Russia)

6. Adrian Nugraha Utama (Indonesia)

7. Selver Pepić (Bosnia-Herzegovina)

8. Ilie Popanu (Moldova)

9. Ion Toloaca (Moldova)

10. Petar Tadic (Montenegro)

11. Andrew Zhao (United States)

12. Lars Dehlwes (Germany)

13. Jakub Supeł (Poland)

14. Teoh Yee Seng (Malaysia)

15. Ng Fei Chong (Malaysia)

16. Ivan Tadeu Ferreira Antunes Filho (Brazil)

17. Cristian Zanoci (Moldova)

18. Kohei Kawabata (Japan)

19. Dinis Cheian (Moldova)

(The list is ordered according to the arrival time)

 

This list of correct solutions is ordered according to the arrival time. There are also two incorrect solutions. The number of registered participants: 259 from 44 countries.

———————–

The hints have been given as follows. For the second week: first, note that the correct solutions submitted thus far can be roughly divided into three categories: (a) fully geometric; (b) fully geometrical constructions, but some geometrical construction elements are motivated arithmetically; (c) first step is done geometrically, the next steps involve measurements (angles and/or distances), calculations, and using the calculation results for drawing. Second, keep in mind that everything you need to know for solving this problem is covered by Formula sheet Eq VI-8 (however, this knowledge needs to be applied creatively).
 

The hints for the last 10 days are aimed to help finding the fully geometric solution and are given in the form of questions to think about. (A) Where does lay the intersection point of the images of two parallel lines? (B) Consider two infinitely distant light sources which are at an angular distance \alpha from each other. What is the angular distance between the images of these sources, as seen from the centre of the lens?

The hints for the last 7 days: use the answer to the question (A) to find one of the focal planes of the lens. On that focal plane, it is possible to mark two points P and Q the images of which are at infinity, separated from each other by an angular distance of 90^\circ. The centre of the lens needs to lie on a certain curve, which can be drawn using the points P and Q, together with the answer to the question (B).

The final hint for the last 4 days: if you were successful in answering the previous questions, you just need to repeat the last steps two find another curve where the center of the lens also needs to lie.


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